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x^2+70x-800=0
a = 1; b = 70; c = -800;
Δ = b2-4ac
Δ = 702-4·1·(-800)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-90}{2*1}=\frac{-160}{2} =-80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+90}{2*1}=\frac{20}{2} =10 $
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